How many types of ions must be present in solution, at minimum, for the phenomenon of selective precipitation to be observed? Your answer should be a whole number without any decimal places.

Two (2) types of ions

Explanation:

Metal ions (cations) and negatively charged ions (anions) of either chloride, carbonate, sulphides or hydroxides are present during the selective precipitation.

Majorly, the process determines the metal ions present by initiating precipitation as certain conditions.

I hope this was helpful.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.