A sample containing dolomite, CaCO3.MgCO3, is treated with 10.00 mL of 1.452 M HCl. The excess HCl is back-titrated with 26.03 mL of 0.1263 M NaOH to reach the end-point
Calculate number of mols of dolomite in the sample.
Hint: The BALANCED equation between dolomite and HCl is:
4HCl + CaCO3. MgCO3 → CaCl2 + MgCl2 + 2H2O + 2002 *
TA

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