An ideal gas with γ = 1.67 has an initial temperature of 0°C, initial volume of 10.0 liters, and initial pressure of 1.00 atm. Then the gas is expanded adiabatically to a volume of 10.4 liters. What is the new temperature? (1 point)

T = 9.74°C

Explanation: An ideal gas in a quasi-static adiabatic process follows the equation: .

So:

constant = 46.7735

Adiabatic conditions can be written as:

Then, new temperature is

T = 9.74°C

The new temperature is 9.74°C.

answer: h+ its less than oh

explanation:

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).