Precision Problems: A group of students worked in separate teams to measure the length of an object.
Here are their data:
Team 1
2.65 cm
Team 2
2.75 cm
Team 3
2.80 cm
Team 4
2.77 cm
Team 5
2.60 cm
Team 6
2.65 cm
Team 7
2.68 cm
I
cm.
• The average length is
This is the mean or average.
cm.
• Subtract the highest value from the lowest value:
This is the range or spread.
• Divide this number by 2:
cm.
This is the approximate range from the average.
• The precision of the measurement can be shown as average range.
The precision of the measurement was
cm.
Demystifying Scientific Data: RET 2006, Rev 2
25

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

Step 2: Get The Range

Step 3: Divide Range by 2

Step 4: Determine the Precision

Substitute 2.70 for Average and 0.1 for Approximate Range

h let me think

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.