write the balanced nuclear equation for the radioactive decay of radium-226 to give radon-222, and determine the type of decay

DEAR THE ANSWER TO YOUR QUESTION IS,

Explanation: Consider the equation for the decay of radium-226 to radon-222, with the simultaneous loss of an alpha particle and energy in the form of a gamma ray. Radium-226 is the reactant; radon, an alpha particle, and a gamma ray are the products. The equation is:

shown in the attach figure

TYPE OF DECAY: as α-particle emmit in this reaction hence its the α-decay

It decays by emitting an alpha particle composed of two protons and two neutrons. The radium nucleus turns into radon-222 nucleus, itself radioactive, containing two protons and two neutrons less. The disintegration releases 4.6 million electronvolts of energy

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possibly, yes.

explanation:

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