The reaction between ammonia and oxygen is given below: 2NH3(g) + 2O2(g) → N2O(g) + 3H2O(l)

We therefore know that which of the following reactions can also occur?

a. 4 NH3(g) + 5 O2(g) > 4 NO(g) + 6 H2O(g)
b. 4 NO(g) + 6 H2O(g)> 4 NH3(g) + 5 O2(g)
c. N2O(g) + 3 H2O(l) > 2 NH3(g) + 2 O2(g)
d. None of the Above

N2O(g) + 3 H2O(l) > 2 NH3(g) + 2 O2(g)

Explanation:

If we look at the reaction stated in the question, we will notice that the option chosen in the answer is the reverse of that reaction.

One thing is clear, if a reaction is possible, then its reverse reaction is equally possible. The equilibrium position may shift towards the forward or reverse reaction based on the conditions of the reaction.

Hence if the reaction, 2NH3(g) + 2O2(g) → N2O(g) + 3H2O(l) is possible, then the reaction, N2O(g) + 3 H2O(l) > 2 NH3(g) + 2 O2(g) is also possible.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

the answer is a for sure mark brainliest i had got this right on usatestprep