According to the following reaction, how many moles of dichloromethane (CH2Cl2) will be formed upon the complete reaction of 0.766 moles methane (CH4) with excess carbon tetrachloride? methane (CH4) (g) + carbon tetrachloride (g) → dichloromethane (CH2Cl2) (g)

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Explanation:

We can start with the reaction, if we know the formula for each compound:

-) Methane:

-) Carbon tetrachloride:

-) Dichloromethane:

With this in mind, we can write the reaction:

Now, we can balance the reaction:

After this, we have 2 carbon atoms on each side, 4 hydrogen atom on each side, and 4 chlorine atoms on each side.

If we want to know how many moles of would be produced with .766 moles of , we have to check the balanced reaction and use the molar ratio. In this case, the molar ratio is 1 mol will produce 2 moles of (1:2). So:

We wil have .

I hope it helps!

the answer is true.

it's filtration, but this is an assumption so my apologies if i got this