How would a decrease in volume affect the following reaction? N2 (g) + O2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. 2NO(g) (1 point) The equilibrium would shift to the right. The equilibrium would shift to the left. There would be no change to equilibrium. The affect on equilibrium cannot be determined.

Explanation:

                        N₂(g) + O₂(g) ⇄ 2NO( g )

We shall apply Le Chatelier's principle to see the effect of decrease in volume or increase in concentration on the effect of state of equilibrium in the reaction given .

In this reaction 1 volume of nitrogen gas reacts with 1 volume of oxygen to give 2 volume of NO gas . In total there is no change in volume due to reaction . So when we change the volume , the concentration of reactant and product will affect the rate of forward and reverse reaction . Overall there will be no change in the state of equilibrium . The equilibrium will neither shift to the right nor will shift to the left.

It will remain unchanged .

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )