Rectangular cube 3.2 m length 1.2 m in height and 5 m in length is split into two parts. The container has a movable airtight divider that divides its length as necessary. Part A has 58 moles of gas and part B has 165 moles of a gas. Required:
At what length will the divider to equilibrium?

The length the divider is to  equilibrium from Part A = 1.30 m and from Part B = 3.70 m

Explanation:

Given that:

A rectangular cube with 3.2 m breadth, 1.2 m height and 5 m in length is splitted into two parts.

The diagrammatic expression for the above statement can be found in the attached diagram below.

The container has a movable airtight divider that divides its length as necessary.

Part A has 58 moles of gas

Part B has 165 moles of a gas.

Thus, the movable airtight divider will stop at a length where the pressure on it is equal on both sides.

i.e

Using the ideal gas equation,

PV = nRT

where, P,R,and  T are constant.

Then :

--- (1)

since Volume of a cube = L × B × H

From the question; the L = 5m

i,e

= 5

From equation (1) , we divide both sides by (B × H)

Then :

By cross multiplying; we have:

165 ( 5 - )  = 58 (

825 - 165  = 58

825 = 165 +58

825 = 223

= 825/223

 = 3.70 m

= 1.30 m

The length the divider is to  equilibrium from Part A = 1.30 m and from Part B = 3.70 m

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error