Would you expect each of the following atoms to gain or lose electrons when forming ions? What ion is the most likely in each case? (And explain why) 1. Ra 2. In 3. P 4. Te 5. Br 6. Rb (I especially need help with the second portion of the question)

(I). The most likely to lose electron is Rubidium

(II). The most likely to lose electron is Bromine

Explanation:

Given that,

Radium, Indium, Phosphorus, Tellurium, Bromine and Rubidium

We know that,

Metal :

They atom which to lose electron these is called metal.

When the atom loses the electron then the positive charge come on the atom.

The most likely to lose electron is Rubidium

Non metal :

They atome which is gains electron. It is called non metal.

So, we can say that, the non metal gains electron.

When the atom gains the electron then the negative charge come on the atom.

The most likely to gain electron is Bromine

Hence, This is required answer.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

the answer is d.) potassium