For a particular reaction, ΔH∘=−28.4 kJ and ΔS∘=−87.9 J/K. Assuming these values change very little with temperature, at what temperature does the reaction change from nonspontaneous to spontaneous?

282 K.

Explanation:

We know that G = H - T * S

If we want to find the temperature that the spontaneity of the reaction changes, we set the free energy equal to 0 and solve for T.

0 = -24.8 + 0.0879 T  (make sure to keep units all the same in terms of kJ)

T = 282 K.

it is stable as it is in group 0 which have full outer shells of electrons

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph