Chemistry, 12.08.2020 05:01 farihasy6508
A certain reaction has an activation energy of 39.5 kJ/mol. As the temperature is increased from 25.0°C to a higher temperature, the rate constant increases by a factor of 5.90. Calculate the higher temperature (in °C).
Answers: 1
![ln\frac{k_2}{k_1} = \frac{E_a}{R} [\frac{1}{T_1} -\frac{1}{T_2} ]](/tpl/images/0718/4272/c6487.png)
![ln\frac{5.9}{1} = \frac{39500}{8.3} [\frac{1}{298} -\frac{1}{T_2} ]](/tpl/images/0718/4272/ff326.png)
![.000373= [\frac{1}{298} -\frac{1}{T_2} ]](/tpl/images/0718/4272/7507e.png)
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A certain reaction has an activation energy of 39.5 kJ/mol. As the temperature is increased from 25....
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