Determine the oxidation state for each of the elements below. The oxidation state of ... silver ... in ... silver oxide Ag2O ... is ... ___ . The oxidation state of sulfur in sulfur dioxide SO2 is ___ . The oxidation state of iron in iron(

The oxidation state of silver in is .

The oxidation state of sulfur in is .

Explanation:

The oxidation states of atoms in a compound should add up to zero.

There are two silver atoms and one oxygen atom in one formula unit of . Therefore:

.

The oxidation state of oxygen in most compounds (with the exception of peroxides and fluorides) is . Silver oxide isn't an exception. Therefore:

.

Solve this equation for the (average) oxidation state of :

.

Similarly, because there are one sulfur atom and two oxygen atoms in each molecules:

.

The oxidation state of in is also , not an exception, either.

Therefore:

.

Solve this equation for the oxidation state of here:

.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.