Odine atoms will combine to form I2 in liquid hexane solvent with a rate constant of 1.5×1010L/mol⋅s. The reaction is second order in I . Since the reaction occurs so quickly, the only way to study the reaction is to create iodine atoms almost instantaneously, usually by photochemical decomposition of I2. Suppose a flash of light creates an initial [I] concentration of 2.00×10−2 M . How long will it take for 94% of the newly created iodine atoms to recombine to form I2? Express your answer using two significant figures.

The time taken is  

Explanation:

From the question we are told that

    The  rate constant is  

    The initial concentration of iodine atom  is  

Generally the integrated  rate law for a second order reaction is  mathematically represented as

Where is the concentration of the remaining iodine atom  after the recombination which is mathematically evaluated as

      [100%  - 94%]

The reason for the 94%  is that we are told from the question that only 94% of the iodine atom recombined

=>  [6%]

=>  

substituting values

So

answer: i would say b.

explanation:

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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