A climber is attached to a vertical rope that has a tension of 785 N. If the climber has a mass of 85 kg, what is the net force on the climber?
O A. 48 N up
OB. 542 N up
O C. 700 N down
O D. 48 N down
SUBMIT

D. 48 N down

Explanation:

Given that:

Mass of climber = 85 kg, Tension on rope = 785 N, acceleration due to gravity = 9.8 m/s²

To calculate the net force on the climber, we need to first calculate the weight of the climber. Since the climber is affected by the earth gravity, the weight of the climber is the product of his mass and the acceleration due to gravity, therefore:

Weight = mass × acceleration due to gravity = 85 kg × 9.8 m/s² = 833 N

The weight of the climber is acting downwards while tension on the rope is acting upwards, therefore:

Net force on the climber = 785 N - 833 N = - 48 N

This means that the net force on the climber is 48 N downwards

i'm not sure

explanation:

i'll try whatever you got

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.