Answer to the best of your ability please

The answer to your question is given below.

Explanation:

To draw the structure of 2–methyl–1–butanamine, we following must be observed:

1. The functional group of the compound is amine –NH2.

2. The functional group is located at carbon 1.

3. The longest continuous carbon chain is carbon 4 i.e butane. Since the functional group is amine, the –e at the end of the butane is replaced with

–amine, making the name to be butanamine.

4. Methyl, CH3 is located at carbon 2.

5. Combine the above to get the structure of 2–methyl–1–butaamine.

Please see attached photo for the structure of 2–methyl–1–butanamine

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml