To what volume will a 2.33 L sample of gas expand if it is heated from 10.0°C to 100.0°C? Group of answer choices 0.233 L 4.41 L 23.3 L 3.76 L 3.07 L

3.07 L

Explanation:

This question describes Charles law, which shows the direct relationship of the absolute temperature to its volume when the pressure is kept constant. The Charles' law equation is:

V1/T1 = V2/T2

Where; V1 is the volume of the gas at an initial state

V2 is the volume of the gas at a final state

T1 is the absolute temperature of the gas at an initial state

T2 is the absolute temperature of the gas at a final state.

According to the question, V1 = 2.33L, V2 = ?, T1 = 10°C, T2 = 100°C

The absolute temperature unit, which is Kelvin, need to be used. Hence, we convert °C to Kelvin using:

T(K) = T(°C) + 273.15

T1 (K) = 10°C + 273.15 = 283.15K

T2 (K) = 100°C + 273.15 = 373.15K

To solve for V2 in the above Charles law equation, we make V2 the subject of the formula by saying:

V2 = V1 × T2 / T1

V2 = 2.33 × 373.15 / 283.15

V2 = 869.4395/ 283.15

V2 = 3.0705

Hence, the gas will be expanded to a volume of 3.07L when heated from 10.0°C to 100.0°C.

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b