Question 22 3 pts
To what volume will a 2.33 L sample of gas expand if it is heated from 10.0°C to 100.0°C?

0.233L
4.41L
23.3 L
3.76 L
3.07 L

3.07L

Explanation:

Charles law, which describes the direct relationship of the absolute temperature to its volume when the pressure is kept constant will be used in this case. The Charles' law equation is:

V1/T1 = V2/T2

Where; V1 is the volume of the gas at an initial state= 2.33L

V2 is the volume of the gas at a final state= ?

T1 is the absolute temperature of the gas at an initial state= 10°C

T2 is the absolute temperature of the gas at a final state= 100°C

The temperature in degree Centigrade (°C) must be converted to the absolute temperature unit (Kelvin) using:

T(K) = T(°C) + 273.15

T1 = 10°C + 273.15 = 283.15K

T2 = 100°C + 273.15 = 373.15K

To solve for V2 in the above Charles law equation, we make V2 the subject of the formula by saying:

V2 = V1 × T2 / T1

V2 = 2.33 × 373.15 / 283.15

V2 = 869.4395/ 283.15

V2 = 3.0705

Hence, the gas will be expanded to a volume of 3.07L when heated from 10.0°C to 100.0°C.