Suppose a 22.092 g sample of a 1:1 mixture of acetylferrocene and ferrocene was separated by column chromatography, and the recovered fractions weighed 9.017 g (acetylferrocene) and 8.075 g (ferrocene), what was the percent recovery of acetylferrocene?

81.6%

Explanation:

mass of acetylferrocene and ferrocene mixture = 22.092 g

mass ratio acetylferrocene and ferrocene mixture = 1 : 1

The sum of the ratios = 2, therefore the mass of each compound will be half the mass of the mixture

mass of each compound in the sample mixture = 1/2 * 22.09 2= 11.046 g

mass of recovered acetylferrocene = 9.017 g

percentage recovery = mass recovered/mass in sample * 100%

percentage recovery of acetylferrocene = (9.017 g / 11.046 g) * 100%

percentage recovery of acetylferrocene = 81.6%

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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dynamic equilibrium is the answer.