a 2.000-g sample of a hydrated copper sulfate is heated and the waters of hydration are removed if that mass of the remaining salt is 1.278 g what was the percentage of water in the original hydrate

36.1%

Explanation:

The following data were obtained from the question:

Mass of hydrated copper sulfate = 2 g

Mass of anhydrous copper sulfate = 1.278 g

Percentage of water =..?

Next, we shall determine the mass of water in the hydrated copper sulfate.

This can be obtained as follow:

Mass of hydrated copper sulfate = 2 g

Mass of anhydrous copper sulfate = 1.278 g

Mass of water =...?

Mass of water = Mass of hydrated copper sulfate – Mass of anhydrous copper sulfate

Mass of water = 2 – 1.278

Mass of water = 0.722 g

Finally, we can obtain the percentage of water in the hydrated copper sulfate as follow:

Mass of water = 0.722 g

Mass of hydrated copper sulfate = 2 g

Percentage of water =..?

Percentage of water = mass of water /mass of hydrate x 100

Percentage of water = 0.722/2 x 100

Percentage of water = 36.1%

Therefore, the percentage of water in the hydrated copper sulfate is 36.1%

oh it is true if thats what you are asking

the answer is option a.