In reaction NH3 →3H2 + N2, how many moles of N2 formed if 2.81 g NH3 dissociate? Show work!

0.0826 mol (corrected to 3 sig. fig.)

Explanation:

First, balance the equation:

2NH3 →3H2 + N2

Take the atomic no. of N=14.0, and H=1.0,

no. of moles = mass / molar mass

So, no. of moles of NH3 dissociated = 2.81 / (14.0+1.0x3)

= 0.165294117mol

From the equation, the mole ratio of NH3:N2 = 2:1, meaning for every 2 moles of NH3 dissociated, one mole of N2 is formed.

So, using this ratio, the no. of moles of N2 formed will be 0.165294117 / 2

=0.0826 mol (corrected to 3 sig. fig.)

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.