A 35 L tank of oxygen is at 42°C with an internal pressure of 5000.mmHg. If the temperature changes to 88°C, what would the new pressure be ? the volume is held constant

5730 mmHg.

Explanation:

The following data were obtained from the question:

Initial temperature (T1) = 42 °C.

Initial pressure (P1) = 5000 mmHg.

Final temperature (T2) = 88 °C.

Final pressure (P2) =.?

Next we shall convert celsius temperature,T(°C) to Kelvin temperature, T(K).

This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T1) = 42 °C.

Initial temperature (T1) = 42 °C + 273 = 315 K

Final temperature (T2) = 88 °C.

Final temperature (T2) = 88 °C + 273 = 361 K

Finally, we shall determine the new pressure.

Since the volume of the container is constant, the new pressure can be obtained as follow:

Initial temperature (T1) = 315 K.

Initial pressure (P1) = 5000 mmHg.

Final temperature (T2) = 361 K.

Final pressure (P2) =.?

P1/T1 = P2/T2

5000/315 = P2/361

Cross multiply

315 x P2 = 5000 x 361

Divide both side by 315

P2 = (5000 x 361) / 315

P2 = 5730.1 ≈ 5730 mmHg

Therefore, the new pressure is 5730 mmHg.

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explanation: