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B, 1.98g

Explanation:

No. of moles = mass / molar mass

no. of moles of Na2SO3 produced = 1.2 / 126.05 =0.009520031mol

From the balanced equation, the mole ratio of NaHSO3:Na2SO3 = 2:1, meaning every 2 moles of NaHSO3 reacted, gives out 1 mole of Na2SO3.

Since 0.009520031mol of Na2SO3 is produced, the no. of moles of NaHSO3 used = 0.009520031 x 2

= 0.019040063 mol

Mass = no. of moles x molar mass

Hence,

mass of NaHSO3 used = 0.019040063 x 104.07

= 1.98 g

= B

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