A balloon is filled with 0.250 mole of air at 35 degrees celsius. If the volume of the balloon is 6.23 liters, what is the absolute pressure of the air in the balloon?

pressure = 1.014atms

Explanation:

use ideal gas

PV=nRT

P = (0.250 x 0.08206 x 308)/(6.23)

P = 1.014 atm

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

c8h10 is your answerr