A neutralization reaction was carried out in a calorimeter. The change in temperature (∆T) of the solution was 10.9 °C and the mass of the solution was 100.0 g. Calculate the amount of heat energy gained by the solution (qsol). Use 4.18 J/(g•°C) as the specific heat, Cs, of the solution

The correct answer is 4,556.2 J

Explanation:

The amount of heat is calculated with the following equation:

Heat= m x Cs x ΔT

Given:

m= 100.0 g (mass)

Cs= 4.18 J/g.ºC (specific heat)

ΔT= 10.9ºC (change in temperature)

We introduce the data in the equation and calculate the heat:

Heat = 100.0 g x 4.18 J/ºC.g x 10.9ºC = 4,556.2 J

Therefore, the amount of heat absorbed by the water (gained by the solution) is 4,556.2 J

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