How many grams of AuCl2, if the compound has 6.3 x10^23 atoms of Cl?

Total mass =  93.21 gram (Approx)

Step-by-step explanation:

Given:

Atoms of Cl = 6.3 × 10²³

Find:

Amount of AuCl₂

Computation:

Molecules of AuCl₂ = 6.3 × 10²³ / 2 = 3.15 × 10²³

1 mol of AuCl₂ = 6.022 × 10²³ molecules

Number of mol = 3.15 × 10²³ /  6.022 × 10²³

Number of mol  = 0.523 mol

So,

Molar mass of AuCl₂ = 267.87 g/mol

Total mass = 0.348 mol × 267.87 g/mol

Total mass =  93.21 gram (Approx)