A solution is prepared by adding 6.24 g of benzene (C 6H 6, 78.11 g/mol) to 80.74 g of cyclohexane (C 6H 12, 84.16 g/mol). Calculate the mole fraction and molality of benzene in this solution.

Explanation:

Hello,

In this case, we can compute the mole fraction of benzene by using the following formula:

Whereas n accounts for the moles of each substance, thus, we compute them by using molar mass of benzene and cyclohexane:

Thus, we compute the mole fraction:

Next, for the molality, we define it as:

Whereas we also use the moles of benzene but rather than the moles of cyclohexane, its mass in kilograms (0.08074 kg), thus, we obtain:

Or just 0.990 m in molal units (mol/kg).

Best regards.

the answer is minerals.