Draw the Lewis structure for the sulfur dioxide molecule. Be sure to include all resonance structures that satisfy the octet rule.

See explanation

Explanation:

We have to remember that the formula of sulfur dioxide is . So, the "S" atom is the central one and the "O" atoms are in the left and right of S. Additionally, "S" and "O" atom has 6 valence electrons each. With this in mind, we can start with a structure in which the left oxygen has 2 lone pairs and a double bond, the S atom can have a double bond a single bond and a lone pair and the right oxygen with 3 lone pairs with a single bond (structure A). Now, if we move the negative charge in the right  (resonance) to the middle and the double bond to the left oxygen we will obtain structure B. Finally, we can move the negative charge in the left to the middle and we will obtain structure C. (See figure 1).