How could you safely determine if a base is stronger than an acid?

If you compare an acid's pKa and a base's pKb, the thing with the lower value is “stronger” in terms of acid or base. If you mix equal amounts of a base with a lower pKb with a substance that has a higher pKa, the resulting solution would be acidic.

Explanation:

If you’re trying to observe a battle of wills between an acid and a base, whichever one forms a solution (of equal molarity and volume, in deionized water) with a pH further away from 7 is stronger. I say equal molarity and volume because this means that an equal number of ions of each substance would be floating around in an equal amount of water.

in theory, limestone is composed principally of the compound calcium carbonate - caco3, but in reality this compound is deposited in conditions involving a number of other compounds as impurities so it ends up being a mixture of many compounds.

hope this : -)

tony (lordcaos066)

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%