What is the value of the equilibrium constant Kcif the concentration of NO and NOBr are 0.10 M and the concentration of Br2 is 3.0 M?
2NOBr(8) = 2NO(g) + Br2(g)

3

Explanation:

Data obtained from the question include:

Concentration of NO, [NO] = 0.1M

Concentration of NOBr, [NOBr] = 0.1M

Concentration of Br, [Br2] = 3M

Equilibrium constant, Kc =..?

The equilibrium constant, Kc is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, the equilibrium constant, Kc for reaction can be obtained as follow:

2NOBr <==> 2NO + Br2

Kc = [NO]² [Br2] /[NOBr]²

[NO] = 0.1M

[NOBr] = 0.1M

[Br2] = 3M

Kc =..?

Kc = [0.1]² [3] /0.1]²

Kc = 3

Therefore, the equilibrium constant Kc, for the reaction is 3.

the answer would be b i believe

i think its 100.

hope this !