What is the theoretical yield of butan-2-one (shown) if 0.30 mL of butan-2-ol is treated with TEMPO and an excess of of TCCA and is completely oxidized? Your answer should be in grams and give only the number. Your answer should have at least 2 significant digits (2nd decimal place).

Theoretical yield = 0.24 gram (Approx)

Explanation:

Given:

Butan-2-1

Molar mass(butan-2-ol) = 74.12 g/mol

Molar mass(butan-2-one) = 72.11 g/mol

Density of butan = 0.806 g/mol

Volume = 0.30 ml

Computation:

Mass of 2-butan = Density of butan × volume

Mass of 2-butan = 0.806 g/mol × 0.30 ml

Mass of 2-butan = 0.2418 g

Mass of product = Mass of 2-butan × [1 mol of butan-2-ol / 74.12] × [1 mol of butan-2-one / 1 mol of butan-2-ol] × [72.11 g/mol / 1 mol of butan-2-one]

Mass of product = 0.235 gram

Theoretical yield = 0.24 gram (Approx)

the answer would be a

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