130I decays by emission of beta particles to form stable 130Xe. A 3.00 g iodine sample containing some I-130 was recorded as having 9487 disintegrations per min. k = 0.00094 min - 1. How many radioactive I-130 atoms are present in the sample?

The number of radioactive atoms present in the sample is 1.01 × 10⁷ atoms.

Emission of Beta Particles takes place when there is a numerous amount of neutron to the proton in the nucleus. As a result, the neutron is transformed to proton (which is retained in the nucleus) and electron which leaves the nucleus under high energy.

Given that:

The rate of disintegration of the radioactive sample per minute is expressed by using the formula:

A = kN

where;

∴

N = 10092553.19 atoms

N = 1.01 × 10⁷ atoms  

Therefore, we can conclude that the number of radioactive atoms present in the sample is 1.01 × 10⁷ atoms.

Learn more about emission of beta particles here:

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its first and third is your answer i did the qustion the fourth isnt right

l dont know l am s sorry