The equilibrium reaction below has the Kc = 4.00 at 25°C. If the temperature of the system at equilibrium is increased to 100°C, how and for what reason will the equilibrium shift. Also show and explain how and why the Kc value will change.

Following are the answer to this question:

Explanation:

In the given question information is missing, that is equation which can be defined as follows:

Growing temperatures may change its connection to just the way which consumes thermal energy in accordance with Le chatelier concepts Potential connection is endothermic. shifts to the right   Kc are described as a related to the concentration by the intensity of both the reaction for each phrase which reaches a power equal towards its stoichiometric equation coefficient  Kc = \frac{product}{reactant}   It increases [product] but reduces [reactant] Therefore, Kc increases

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.