A neutralization experiment using NaOH and HCl produced 716J. The limiting reactant was NaOH, which was present in 1.254102 moles. Calculate the enthalpy change of neutralization (in kJ/mol).

Give your answer to three significant figures.

The enthalpy change of neutralization is 0.571 kJ/mol

Explanation:

The balanced chemical reaction for neutralization experiment using NaOH and HCl will be :

As NaOH is the limiting reagent, which is 1.254102 moles which will decide how much heat is released.

When 1.254102 moles of NaOH reacts, heat released will be = 716 J

Thus 1 mole moles of NaOH reacts, heat released will be =     (1kJ=1000J)

Thus the enthalpy change of neutralization is 0.571 kJ/mol

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne