Answers: 3
![[ICI]_{eq}=0.271M](/tpl/images/0705/0745/27a40.png)
![[I_2]_0=[Cl_2]_0=\frac{0.45mol}{2.0L}= 0.225M](/tpl/images/0705/0745/f16cc.png)
due to the reaction extent:![Kc=\frac{[ICI]^2}{([I_2])([CI_2])} \\\\Kc=\frac{(2x)^2}{([I_2]_0-x)([CI_2]_0-x)} \\\\9.09=\frac{(2x)^2}{(0.225-x)(0.225-x)}](/tpl/images/0705/0745/ac0ef.png)
![[ICI]_{eq}=2*0.135M](/tpl/images/0705/0745/888be.png)
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What is the equilibrium concentration of ICl if 0.45 mol of I2 and 0.45 mol of Cl2 are initially mix...
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