How many moles of sulfur trioxide will be produced when the complete combustion of 100.0 g of sulfur dioxide takes place

1.563 moles of SO3.

Explanation:

We begin by calculating the number of mole present in 100g of sulphur dioxide, SO2. This can be obtained as follow:

Molar mass of SO2 = 32 + (16x2) = 64g/mol

Mass of SO2 = 100g

Mole of SO2 =..?

Mole = mass/Molar mass

Mole of SO2 = 100/64

Mole of SO2 = 1.563 mole

Now, we can obtain the number of mole of sulphur trioxide, SO3 produce from the reaction as follow:

2SO2 + O2 —> 2SO3

From the balanced equation above,

2 moles of SO2 reacted to produce 2 moles of SO3.

Therefore, 1.563 moles of SO2 will also react to produce 1.563 moles of SO3.

Therefore, 1.563 moles of SO3 is obtained from the reaction.

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong