For the given reaction, what volume of CO2 can be produced from 0.90 L of O2 , assuming an excess of CO ? Assume the temperature and pressure remain constant. g

1.8L of CO2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CO + O2 —> 2CO2

Next we shall determine the volume of O2 that reacted and the volume of CO2 produced from the balanced equation. This is illustrated below:

1 mole of O2 reacted

Recall: 1 mole of any gas occupy 22.4L at stp

Therefore 1 mole of O2 = 22.4L

2 moles of CO2 were produced

2 moles of CO2 = 2 x 22.4 = 44.8L

Summary:

From the balanced equation above,

22.4L of O2 reacted to produce 44.8L of CO2.

Finally, we shall determine the volume of CO2 produced from 0.90L of O2. This can be obtained as follow:

From the balanced equation above,

22.4L of O2 reacted to produce 44.8L of CO2.

Therefore, 0.90L of O2 will react to produce = (0.9 x 44.8)/22.4 = 1.8L of CO2.

Therefore, 1.8L of CO2 were produced.

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but