A certain shade of blue has a frequency of 7.30×1014 Hz. What is the energy of exactly one photon of this light? Planck's constant ℎ=6.626×10−34 J⋅s.

The energy of exactly one photon of this light is 4.84*10⁻¹⁹ Joules

Explanation:

A photon is an elementary particle that, according to the principles of quantum physics, makes up light.

A photon is characterized by a wavelength, denoted by λ, or, by an energy, denoted by E.

The relationship between the amount of energy (E) transported by the photon, and its frequency (v), is determined by:

E= h*v

where, as mentioned, E is the energy v is the frequency and h is the Planck constant, whose value is 6,626 * 10⁻³⁴ Joules-sec.

In this case, the frecuency is 7.30*10¹⁴ Hz. Then:

E=6,626 * 10⁻³⁴ Joules-sec* 7.30*10¹⁴ Hz

Solving:

E= 4.84*10⁻¹⁹ Joules

The energy of exactly one photon of this light is 4.84*10⁻¹⁹ Joules