A solution of is found to have 37% transmittance at 447 nm. If the molar absorption coefficient (ε) is 4400 at 477 nm, what is the concentration of in the solution? (Assume the path length is 1 cm) Please insert the answer according to the following example: 1.0 x 10^-1 M.

The concentration of the solution is 1.068×10⁻⁴M

Explanation:

Hello,

To find the concentration of the solution, we'll have to use Beer-Lambert law which states absorption is directly proportional to the concentration of the solution.

Beer-Lambert law = A = εCL

A = absorption = 2 - log₁₀%T = 2 - log₁₀(34)

A = 2 - 1.5314 = 0.47

A = 0.47

ε = molar absorption coefficient = 4400

C = concentration of the solution

L = path length = 1cm

A = εcl

C = A / εl

C = 0.47 / 4400 × 1

C = 1.068×10⁻⁴M

The concentration of the solution is 1.068×10⁻⁴M

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.