The Rf value of compound A is 0.35 when TLC plate is developed in hexane and 0.45 when the plate is developed in diethyl ether. Compound B has an Rf value of 0.45 in hexane and 0.60 in diethyl ether. Hexane would be better for separating a mixture of compounds A and B by TLC. If yes then why?

No.

Explanation:

Under TLC chromatography, the compounds are separated based on the different affinity between stationary phase and mobile phase. The higher difference between Rf's of the compounds will produce the better separation.

In Hexane compound A has a Rf of 0.35 and compound B of 0.45.

The difference is 0.45 - 0.35 = 0.10

In dietyl ether, Rf of compound A is 0.45 and for compound B is 0.60.

The difference is 0.60 - 0.45 = 0.15.

As the difference in Rf is higher for dietyl ether:

Hexane would be better for separating a mixture of compounds A and B by TLC. NO. The better separation would be using dietyhl ether.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally