Determine the quantity (g) of pure CaCl2 in 7.5 g of CaCl2•9H2O. Show your work.

The quantity of pure in 7.5 g of is 3.0 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number of particles.

To calculate the moles, we use the equation:

As 1 mole of contains = 1 mole of

Thus 0.027 moles of contains = mole of

Mass of

Thus the quantity of pure in 7.5 g of is 3.0 g

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.