2 metercube of air kept in a vessal at 1 bar pressure is transferred into a 5 meter cube vessel find the pressure of the gas

pressure of the gas P2=0.4bar

Explanation:

According to Boyles law which states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

Boyle's Law gives the relationship between the Pressure and Volume of a gas.

It can be expressed as;

P1V1 = P2V2

P1V1 = P2V2

Where

P1 = Initial Pressure

V1 = Initial Volume

P2 = Final Pressure

V2 = Final Volume

Given:

V1= 2m^3

V2= 5m^3

P1= 1bar

P2=?

P1V1=P2V2

P2=P1V1/V2

Then let us substitute,we have

P2= (1*2)/5

Therefore, pressure of the gas P2=0.4bar

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