The iodine clock experiment consists of the following three reactions, where Reaction 1 is slow relative to Reactions 2 and 3. Predict what would happen if Reaction 2 was slow relative to Reaction 1 Reaction 1:3I^- (aq) + S_2O_8^2- (aq) rightarrow I_3^-, (aq) + 2SO_4^2- (aq) slow
Reaction 2: l_3^-(aq) + 2S_2O_3^2- (aq) rightarrow 3I^- (aq) + S_4O_6^2- (aq) fast
Reaction 3: l_3^- (aq) + starch (aq) rightarrow 3I^ starch (bluish black) fast
A. A color change would appear immediately because I_3^+, would be removed slowly from solution, and would therefore be able to react with starch.
B. The reaction would turn blue slower because I_3^-, is removed at a slower rate.
C. The rate of color change would indicate the rate of reaction 3 instead of reaction 1
D. Reaction 3 would not occur.

A color change would appear immediately because , would be removed slowly from solution, and would therefore be able to react with starch, is the correct answer.

Explanation:

As the given reaction 2 is as follows.

If this reaction is slow then the removal of will be slow in nature.

Since, reaction 3 is fast which is as follows.

As reaction 3 is fast in nature then more amount of starch will react with .

Therefore, we can conclude that a color change would appear immediately because , would be removed slowly from solution, and would therefore be able to react with starch.

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .

the ratio of the conjugate base to the acid required to attain the desired ph.