Consider the expected splitting of the C2 proton signal in the 1H NMR spectrum of 2-ethyl-1,3-propanediol. Presuming that the coupling constants for neighboring protons are sufficiently different, and that the instrument has sufficient resolving power, what is the theoretical multiplicity of the C2 proton signal? a. 12
b. 15
c. 0
d. 6

Seven

Explanation:

In this case, in the middle carbon; (carbon 2) we have 3 neighbors. In the left and right carbon, we have 4 hydrogens in total. In the top carbon, we have 2 hydrogens also, so, in total, we have 6 hydrogens. If we follow the n+1 rule, we will have:

n= 6

signals= n + 1 = 6 + 1 = 7

So, we will have a signal of 7 (a septet).

See figure 1

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