What Volume Of Oxygen react with carbon monooxide to produce 0.5 mole of carbon dioxide at STP?

6000cm3

Explanation:

2CO+O2> 2CO2

CO:CO2

1: 1

CO= 0.5 moles

CO:O2

2:1

O2 moles= 0.5÷2

=0.25moles

1 mole> 24000cm3

0.25moles

(0.25x24000)÷1

= 6000cm3

away from the curb

explanation:

the wheels would then hit the curb if it started to rolling, decreasing the chance of an accident.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%