What is the voltage of an electrolytic cell with copper and magnesium electrodes?

A. 2.71 V

B. -2.71 V

C. 2.03 V

D. -2.03 V

A. 2.71 V

Explanation:

The standard reduction potential, E° of the metals are as follows:

Mg²⁺ + 2e⁻ ⇌  Mg; E° = -2.372

Cu²⁺ + 2e⁻ ⇌  Cu; E° = +0.337

Since magnesium has the the lower E°, it will serve as the anode in the electrolytic cell while copper will serve as the cathode.

At the anode; Mg ⇌  Mg²⁺ + 2e⁻, E° = -2.372

At the cathode; Cu²⁺ + 2e⁻ ⇌  Cu, E° = +0.337

EMF of the cell = E° cathode - E° anode = 0.337 - (-2.372) = 2.71 V

Therefore, EMF of the cell is 2.71 V

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

the awnser is group 12