Dinitrogen pentoxide decomposes to form nitrogen dioxide oxygen, following the equation 2N2O3 - 4NO, + 0,. At a certain timepoint, N2O5 is being consumed at a rate of 0.1 M/s. What's the rate of production of NO, and O, at the
same timepoint?
A. NO, is produced at 0.2 M/s, and O, is produced at 0.05 M/s.
B. NO, is produced at 0.2 M/s, and O, is produced at 0.2 M/s.
C. NO, is produced at 0.05 M/s, and O2 is produced at 0.2 M/s.
D. NO, is produced at 0.1 M/s, and O, is produced at 0.05 M/s.

A. N₂O₅ is produced at 0.2 mol·L⁻¹s⁻¹, and O₂ is produced at 0.05 mol·L⁻¹s⁻¹.  

Explanation:

2N₂O₅ ⟶ 4NO₂ + O₂

For every two molecules of N₂O₅ that disappear, we get four molecules of NO₂ and one of O₂.

NO₂ is forming twice as fast, and O₂ is forming half as fast, as N₂O₅ is decomposing.

N₂O₅ is decomposing at a rate of 0.1 mol·L⁻¹s⁻¹.

So, N₂O₅ is produced at 0.2 mol·L⁻¹s⁻¹, and O₂ is produced at 0.05 mol·L⁻¹s⁻¹.

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.