Aluminum chloride (AICl3) is used in refining petroleum and manufacturing rubber and lubricants. How many formula units are in a 35.6 g sample of aluminum
chloride?

mass change to mol

molar mass of ALCL3 = 133.5

mol = molar mass/mass

= 133.5/35.6

= 3.75 mol

number of formula units

= 3.75 mol × 6.02×10²³

= 2.258×10²⁴

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