Chemistry, 21.06.2020 03:57 rileyeddins1010
4. Set-up ONLY the equation for determining the bond dissociation energy ΔH° for the hydrogenation of acetylene, C2H2 in the reaction below by showing what bonds are being broken (yes, draw Lewis Structures!) and what bonds are being formed: H-C=C-H(g) + 2 H2(g) → CH3-CH3(g)
Answers: 3
![\Delta H=[(1\times B.E_{C\equiv C})+(2\times B.E_{C-H})}+(2\times B.E_{H-H}) ]-[(1\times B.E_{C-C})+(6\times B.E_{C-H})]](/tpl/images/0691/2872/187e8.png)
![\Delta H=\sum [n\times B.E(reactant)]-\sum [n\times B.E(product)]](/tpl/images/0691/2872/42942.png)
![\Delta H=[(n_{H-C\equiv C-H}\times B.E_{H-C\equiv C-H})+(n_{H_2}\times B.E_{H_2}) ]-[(n_{CH_3-CH_3}\times B.E_{CH_3-CH_3})]](/tpl/images/0691/2872/fadbe.png)
![\Delta H=[(1\times B.E_{C\equivC})+(2\times B.E_{C-H})}+(2\times B.E_{H-H}) ]-[(1\times B.E_{C-C})+(6\times B.E_{C-H})]](/tpl/images/0691/2872/5ee06.png)
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