What is the concentration of a CaBr2 solution if 125.00 g of solute was dissolved in enough water to form 250. ml of solution?

Concentration can be defined in terms of molarity. The molarity has been the moles of solute present in a liter of solution.

Moles of can be calculated as:

Moles =

Molecular weight of = 199.89 g/mol

Moles of   =

Moles of = 0.625 mol.

Volume of solution = 250 ml

1000 ml  = 1 L

250 ml = 0.25 L

Molarity =

Molarity =

Molarity = 2.50 M.

The concentration of 125 grams, 250 ml solution has been 2.50 M.

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2.50M

Explanation:

Concentration of a solution describes how much of a solute is dissolved in a solvent in a solution. Molarity of a solution is one way to calculate the concentration of a solution.

The Molarity, M is calculated using the formula: number of moles (n) / volume of solution (litres).

To calculate, the number of moles (n), we say that number of moles = mass of solute / molar mass

In this case, CaBr2 (Calcium Bromide) solution is used where mass no of Calcium (Ca) is 40g/mol and Bromine (Br) is 79.9g/mol

Molar mass of CaBr2= 40 + 79.9(2)

40 + 159.8 = 199.8

Hence, molar mass of CaBr2 is 199.8g/mol

Mass of solute= 125grams

Number of moles (n) of CaBr2 = 125/199.8 = 0.6256

n = 0.6256moles

Volume of CaBr2 solution is 250millilitres(ml). Since, 1000ml= 1L, then 250ml is 250/1000 L

= 0.25L

Molarity of solution (M) = number of moles (n)/ volume of solution (litres)

M = 0.6256/0.25

M= 2.5

Thus, the molarity (concentration) of the solution is 2.5M

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

i belive it is water